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The resistance per centimeter of a meter bridge wire is r, with $X Ω$ resistance in left gap. Balancing length from left end is at 40 cm with $25 Ω$ resistance in right gap. Now the wire is replaced by another wire of 2r resistance per centimeter. The new balancing length from left for same settings will be

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20 cm

80 cm

40 cm

10 cm

answer is B.

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Detailed Solution

$\frac{X}{R} = \frac{ℓ}{100 - ℓ}$
For same X and R balancing length will not change even though metre bridge wire resistance per unit length changes.

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