The resistance R=VI where V=(100±5)volt and I=(10±0.2)amp . Find the percentage error in R

V=100±5 I=10±0.2R=VI∆RR=∆VV+∆II = 5100+0.210 = 5100+2100 = 7100∆RR×100=7%

The resistance R=VI where V=(100±5)volt and I=(10±0.2)amp . Find the percentage error in R

V=100±5 I=10±0.2R=VI∆RR=∆VV+∆II = 5100+0.210 = 5100+2100 = 7100∆RR×100=7%

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The resistance $R = \frac{V}{I}$ where $V = (100 \pm 5) v o l t$ and $I = (10 \pm 0.2) a m p$ . Find the percentage error in R

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$V = 100 \pm 5$

$I = 10 \pm 0.2$

$R = \frac{V}{I}$

$\frac{∆ R}{R} = \frac{∆ V}{V} + \frac{∆ I}{I}$

= $\frac{5}{100} + \frac{0.2}{10}$

= $\frac{5}{100} + \frac{2}{100}$

= $\frac{7}{100}$

$\frac{∆ R}{R} \times 100 = 7 %$

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The resistance R=VI where V=(100±5)volt and I=(10±0.2)amp . Find the percentage error in R

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The resistance $R = \frac{V}{I}$ where $V = (100 \pm 5) v o l t$ and $I = (10 \pm 0.2) a m p$ . Find the percentage error in R