The resistivity of 0.4 M solution of an electrolyte is 10×10−3 ohm-cm its molar conductivity is _____________ ×104 ohm−1 cm2 mol−1

Resistivity ρ=10×10−3 ohm –cmMolarity M = 0.4 MλM=1ρ×1000M=110×10−3×10000.4=25×104=25

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The resistivity of 0.4 M solution of an electrolyte is $10 \times 10^{- 3}$ ohm-cm its molar conductivity is _____________ $\times 10^{4} o h m^{- 1} c m^{2} m o l^{- 1}$

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answer is 25.

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Resistivity $ρ = 10 \times 10^{- 3}$ ohm –cm

Molarity M = 0.4 M

$λ_{M} = \frac{1}{ρ} \times \frac{1000}{M} = \frac{1}{10 \times 10^{- 3}} \times \frac{1000}{0.4} = 25 \times 10^{4} = 25$

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