The resistivity of a 0.8 M solution of an electrolyte is 5×10−3ohm cm. Then its molar conductivity in ohm−1cm2mol−1 is ?

∧m=K×1000Molarity or ∧m=1p×1000Molarity=15×10−3×10000.8=25×104

The resistivity of a 0.8 M solution of an electrolyte is 5×10−3ohm cm. Then its molar conductivity in ohm−1cm2mol−1 is ?

∧m=K×1000Molarity or ∧m=1p×1000Molarity=15×10−3×10000.8=25×104

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The resistivity of a 0.8 M solution of an electrolyte is $5 \times 10^{- 3} o h m c m$ . Then its molar conductivity in $o h m^{- 1} c m^{2} m o l^{- 1}$ is ?

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$25 \times 10^{- 4}$

$5 \times 10^{3}$

$4 \times {10^{-}}^{3}$

$25 \times 10^{4}$

answer is D.

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Detailed Solution

$\land_{m} = \frac{K \times 1000}{M o l a r i t y} o r \land_{m} = \frac{1}{p} \times \frac{1000}{M o l a r i t y}$

$= \frac{1}{5 \times 10^{- 3}} \times \frac{1000}{0.8} = 25 \times 10^{4}$

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The resistivity of a 0.8 M solution of an electrolyte is 5×10−3ohm cm. Then its molar conductivity in ohm−1cm2mol−1 is ?

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The resistivity of a 0.8 M solution of an electrolyte is $5 \times 10^{- 3} o h m c m$ . Then its molar conductivity in $o h m^{- 1} c m^{2} m o l^{- 1}$ is ?