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The resonance energy of N₂O from the following data is $- " x "$ kJ/mol. What is the value of “x” ?
$Δ_{f} H^{0} o f N_{2} O = 82 K J m o l^{- 1}, N \equiv N, 946 K J m o l^{- 1} N = N, 418 K J m o l^{- 1}; O = O, 498 K J m o l^{- 1}, N = O, 607 K J m o l^{- 1}$

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answer is 88.

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Detailed Solution

$Δ_{f} H^{0} c a l \Rightarrow F o r m a t i o n o f N_{2} O$

$N \equiv N_{(g)} + \frac{1}{2} O = O_{(g)} \to N = N = O$

$Δ H^{0} c a l = [B . E_{N \equiv N} + \frac{1}{2} B E_{O = O}] - [B . E_{N = N} + B E_{N = O}]$

$= [946 + \frac{1}{2} (498)] - [418 + 607] = 170 K J m o l^{- 1}$

Resonance energy $Δ_{f} H^{0} (o b s) - Δ_{f} H^{0} (c a l) = 82 - 170 = - 88 K J m o l^{- 1}$

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