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Q.

The rest energy of an electron is 0.511 MeV. The electron is accelerated from rest to a velocity 0.5 C. The change in its energy will be175=0.115

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a

0.105 MeV

b

0.079 MeV

c

0.051 MeV

d

0.026 MeV

answer is C.

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Detailed Solution

\Delta = m{c^2} - {m_0}{c^2} = \frac{{{m_0}{c^2}}}{{\sqrt {1 - ({v^2}/{c^2})} }} - {m_0}{c^2}

= {m_0}{c^2}\left( {\frac{1}{{\sqrt {1 - ({v^2}/{c^2})} }} - 1} \right) = 0.511\,\left( {\frac{1}{{\sqrt {0.75} }} - 1} \right)

= 0.079 MeV

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