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The rest mass of the deuterion $_{1}^{2} H$ , is equivalent to an energy of 1876 MeV, the rest mass of a proton is equivalent to 939 MeV and that of a neutron to 940 MeV. A deuteron may disintegrate to a proton and a neutron if it

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emits a $γ$ -ray photon of energy 2 MeV

captures a $γ$ -ray photon of energy 2 MeV

emits a $γ$ -ray photon of energy 3 MeV

captures a $γ$ -ray photon of energy 3 MeV

answer is D.

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Detailed Solution

${}_{1}H^{2} \to {}_{1}p^{1} + {}_{0}n^{1}$

$∆ E = E_{p r o d} - E_{r e a c t} = 939 + 940 - 1876 = 3 MeV$

Hence, energy is required for the disintegration.

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