The result of the three vectors OA¯, OB¯ and OC¯ has magnitude (R = Radius of the circle)

Resultant =OA2+OC2+OBResultant R1=2R+R=2+1R

The result of the three vectors OA¯, OB¯ and OC¯ has magnitude (R = Radius of the circle)

Resultant =OA2+OC2+OBResultant R1=2R+R=2+1R

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The result of the three vectors $\bar{OA}, \bar{OB} and \bar{OC}$ has magnitude (R = Radius of the circle)

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$\sqrt{2} R$

$(1 + \sqrt{2}) R$

$(\sqrt{2} - 1) R$

$2 R$

answer is B.

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Resultant $= \sqrt{O A^{2} + O C^{2}} + O B$

Resultant $R^{1} = \sqrt{2} R + R = (\sqrt{2} + 1) R$

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The result of the three vectors OA¯, OB¯ and OC¯ has magnitude (R = Radius of the circle)

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The result of the three vectors $\bar{OA}, \bar{OB} and \bar{OC}$ has magnitude (R = Radius of the circle)