Q.

The resultant of  A and B is R1 . On reversing one vector, the resultant becomes R2.The value of R12+R22

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a

A2B2

b

A2+B2

c

2A2B2

d

2A2+B2

answer is C.

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Detailed Solution

R¯1=A¯+B¯

R¯2=A¯B¯     R12=A2+B2+2ABcosθ

+R22=A2+B22ABcosθ¯

      R12+R22=2A2+B2

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