The resultant of two vectors P→&Q→ is R→ . If the magnitude of Q→ is doubled the new resultant becomes perpendicular to P→ then magnitude of R→ is

R2 = P2 +Q2 + 2PQ cosθ when Q is doubledtan90=2QsinθP+2Qcosθ P+2Qcosθ=0 2Qcosθ=-P

The resultant of two vectors P→&Q→ is R→ . If the magnitude of Q→ is doubled the new resultant becomes perpendicular to P→ then magnitude of R→ is

R2 = P2 +Q2 + 2PQ cosθ when Q is doubledtan90=2QsinθP+2Qcosθ P+2Qcosθ=0 2Qcosθ=-P

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The resultant of two vectors $\vec{P} & \vec{Q}$ is $\vec{R}$ . If the magnitude of $\vec{Q}$ is doubled the new resultant becomes perpendicular to $\vec{P}$ then magnitude of $\vec{R}$ is

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$\frac{P^{2} - Q^{2}}{2 PQ}$

$\frac{P}{Q}$

$\frac{P + Q}{P - Q}$

answer is C.

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R² = P² +Q² + 2PQ cos $θ$ when Q is doubled

$\tan 90 = \frac{2 Q \sin θ}{P + 2 Q \cos θ} P + 2 Q \cos θ = 0 2 Q \cos θ = - P$

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The resultant of two vectors P→&Q→ is R→ . If the magnitude of Q→ is doubled the new resultant becomes perpendicular to P→ then magnitude of R→ is

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The resultant of two vectors $\vec{P} & \vec{Q}$ is $\vec{R}$ . If the magnitude of $\vec{Q}$ is doubled the new resultant becomes perpendicular to $\vec{P}$ then magnitude of $\vec{R}$ is