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Q.

The reversible expansion of an ideal gas under adiabatic and isothermal conditions is shown in the figure. Which of the following statement is incorrect?

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a

T1=T2

b

ΔUisothermal>ΔUadiabatic

c

Wisothermal>Wadiabatic

d

T3>T1

answer is A.

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Detailed Solution

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In an isothermal process, temperature is constant T2=T1

Area under P-V graph is more in isothermal Wisothermal>WadiabaticNowΔUisothermal=0

In adiabatic T1V1γ1=T3V3γ1T2T1=(V1V3)γ1. T3<T1 hence internal energy decreases ΔUisothermal>ΔUadiabatic

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