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Q.

The right option for the mass of CO₂ produced by heating 20 g of 20% pure limestone is (Atomic mass of Ca = 40)
$[{CaCO}_{3} \overset{1200 k}{\to} CaO + {CO}_{2}]$

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a

1.76 g

b

2.64 g

c

1.32 g

d

1.12 g

answer is C.

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Detailed Solution

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Mass of CO₂ liberated from 100% pure
${CaCO}_{3} = \frac{20}{100} \times 44 gm$
Mass of CO₂ from 20%
$= \frac{20}{100} \times \frac{44}{5} = 1.76 gm$

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