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Q.

The right option for the mass of CO2 produced by heating 20 g of 20% pure limestone is (Atomic mass of Ca = 40)
CaCO3→1200kCaO+CO2

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a

1.76 g

b

2.64 g

c

1.32 g

d

1.12 g

answer is C.

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Detailed Solution

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Mass of CO2 liberated from 100% pure
CaCO3=20100×44gm
Mass of CO2 from 20%
=20100×445=1.76gm

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