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Q.

The RMS velocity of Nitrogen gas molecules is ‘v’ cm/sec at a certain temperature when the temperature is doubled, The molecules dissociate into individual atoms Now the RMS velocity of the Nitrogen atom is x V cm/see then the value of 'x'' is ______________

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answer is 2.

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Detailed Solution

$\frac{C_{N_{2}}}{C_{N}} = \frac{V}{C_{N}} = \sqrt{\frac{T_{1}}{28} \times \frac{14}{2 T_{1}}} = \frac{1}{2}$

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