The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5 x 104cm s-1 to 10 x 104cm s-1. Which statement might correctly explain how the change accomplished?

PV=13mu2; at const. V: P1P2=u12u22 =(5×104)2(10×104)2=14

The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5 x 104cm s-1 to 10 x 104cm s-1. Which statement might correctly explain how the change accomplished?

PV=13mu2; at const. V: P1P2=u12u22 =(5×104)2(10×104)2=14

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The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5 x 10⁴cm s^-1 to 10 x 10⁴cm s^-1. Which statement might correctly explain how the change accomplished?

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By heating the gas, the temperature is doubled

BV heaing the gas, the pressure is made three times

BV heating the gas, the pressure is made four times

By heating the gas, the volume is tripled

answer is B.

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Detailed Solution

$PV = \frac{1}{3} {mu}^{2}; at const. V : \frac{P_{1}}{P_{2}} = \frac{u_{1}^{2}}{u_{2}^{2}} = \frac{{(5 \times 10^{4})}^{2}}{{(10 \times 10^{4})}^{2}} = \frac{1}{4}$

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The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5 x 104cm s-1 to 10 x 104cm s-1. Which statement might correctly explain how the change accomplished?

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The root mean square speed of an ideal gas in a closed container of fixed volume is increased from 5 x 10⁴cm s^-1 to 10 x 10⁴cm s^-1. Which statement might correctly explain how the change accomplished?