The root mean square velocity $V_{rms}$ , the average velocity $\bar{V}$ and the most probable velocity $V_{mp}$ of the molecules of the gas are in the order

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$\bar{V} > V_{mp} > V_{rms}$

$V_{mp} > \bar{V} > V_{ms}$

$V_{mp} > V_{rms} > \bar{V}$

$V_{rms} > \bar{V} > V_{mp}$

answer is B.

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Detailed Solution

We know that
$v_{rms} = \sqrt{(\frac{3 kT}{m})}, \bar{v} = \sqrt{(\frac{8 kT}{mπ})}$
and $v_{mp} = \sqrt{(\frac{2 kT}{m})}$
$∴ V_{rms} > \bar{V} > V_{mp}$

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