Q.

The roots of the quadratic equation 2x2+ax-a2=0 are [[1]] and [[2]].


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answer is - A, A 2.

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Detailed Solution

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The roots of the quadratic equation 2x2+ax-a2=0 are a2 and -a.
Given quadratic equation is,
2x2+ax-a2=0.
We know that,
Discriminant for the quadratic equation ax2+bx+c=0, a0 where a, b and c are real numbers is given by,
D=b2-4ac.
On comparing the given equation 2x2+ax-a2=0 with standard form we get,
a=2,b=,c=-a2 Then,
D=b2-4ac D=a2-4×2×(-a2) D=a2+8a2
D=9a2 >0                                         Discriminant is greater than zero which means the roots of the equation exist.
Since, quadratic formula for the quadratic equation ax2+bx+c=0, a0 where a, b and c are real numbers is given by,
x=-b±D2a Then,
x=-a±9a22×2 x=-a±3a4
On taking positive sign,
x=-a+3a4 x=2a4
x=a2
On taking negative sign,
x=-a-3a4 x=-4a4
x=-a
Therefore, the roots of the equation 2x2+ax-a2=0 are a2 and -a.
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