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Q.

The roots of the quadratic equation $4 x^{2} + 6 x - 1 = 0$ are

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a

real and equal

b

real and reciprocal

c

real and distinct

d

not real

answer is D.

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Detailed Solution

$4 x^{2} + 6 x - 1 = 0$

$b^{2} - 4 a c = {(6)}^{2} - 4 (4) (- 1)$

$= 36 + 16$

$= 52$

$b^{2} - 4 a c > 0 \Rightarrow$ real and distinct

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