The same colour of light takes t1 s and t2 s to travel the same distance ‘x’ in tow media A and B respectively. Refractive of A w.r.t. B is

BμA=μAμB=CBCA BμA=xBtBxAtA=xBtAxAtB=xt1xt2 BμA=t1t2

The same colour of light takes t1 s and t2 s to travel the same distance ‘x’ in tow media A and B respectively. Refractive of A w.r.t. B is

BμA=μAμB=CBCA BμA=xBtBxAtA=xBtAxAtB=xt1xt2 BμA=t1t2

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The same colour of light takes t₁ s and t₂s to travel the same distance ‘x’ in tow media A and B respectively. Refractive of A w.r.t. B is

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$\frac{t_{1}}{t_{2}}$

$\frac{t_{2}}{{xt}_{1}}$

$\frac{t_{2}}{t_{1}}$

$\frac{{xt}_{1}}{t_{2}}$

answer is D.

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Detailed Solution

$\begin{array}{l} _{B} μ_{A} = \frac{μ_{A}}{μ_{B}} = \frac{C_{B}}{C_{A}} \\ _{B} μ_{A} = \frac{\frac{x_{B}}{t_{B}}}{\frac{x_{A}}{t_{A}}} = \frac{x_{B} t_{A}}{x_{A} t_{B}} \\ = \frac{{xt}_{1}}{{xt}_{2}} \\ _{B} μ_{A} = \frac{t_{1}}{t_{2}} \end{array}$