Q.

The same quantity of electricity is passed through 0.1M H2SO4 and 0.1M HCl. The amounts of H2 obtained at the cathodes are in the ratio

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a

3 : 1

b

2 : 1

c

1 : 2

d

1 : 1

answer is A.

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Detailed Solution

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In both cases H+  is reduced.Therefore same amount of electricity can reduce an equal amount of H+ from both solutions
Hence ,  Amount of H2​ liberated in equal.
Therefore,   Ratio  is 1 : 1

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The same quantity of electricity is passed through 0.1M H2SO4 and 0.1M HCl. The amounts of H2 obtained at the cathodes are in the ratio