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The satellite of mass 1000 kg is supposed to orbit the earth at a height of 2000km above the earth surface. The K.E and P.E respectively are

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5.2 \times 10^{8} J & 1.04 \times 10^{9} J

2.4 \times 10^{10} J & 4.8 \times 10^{10} J

3.7 \times 10^{8} J & 7.4 \times 10^{8} J

7.4 \times 10^{8} J & 3.7 \times 10^{8} J

answer is B.

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Detailed Solution

m = 10^{3} kg,

$h = 2 \times 10^{6} m$

$K= \frac{GMm}{2 (R + h)}$

$= \frac{6.675 \times 10^{- 11} \times 6 \times 10^{24} \times 10^{3}}{2 (6.4 \times 10^{6} + 2 \times 10^{6})} = 2.4 \times 10^{10} J$

$P = \frac{GMm}{(R + h)} = 4.8 \times 10^{10} J$

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