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Q.

The scale of a galvanometer of resistance $2 Ω$ contains 25 divisions. Its current sensitivity is 0.1 mA per division. The series resistance required to convert it into a voltmeter of range 5 V is

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a

998 Ω

b

990 Ω

c

992 Ω

d

1998 Ω

answer is D.

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Detailed Solution

$V = i_{g} (G + R)$

$\Rightarrow 5 = (0.1 \times 10^{- 3} \times 25) (2 + R)$

$\Rightarrow R = 1998 Ω$

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