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The scale of a spring balance which can measure from 0 to 10 kg is 0.25 m long. If a body suspended from this balance oscillates with a time period $\frac{π}{10}$ seconds, neglecting the mass of the spring, find the mass of the body suspended.

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0.98 kg

20 kg

7 kg

1 kg

answer is A.

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Detailed Solution

$T = 2 π \sqrt{\frac{m}{k}} = 0.1 \times π$

$\begin{array}{l} W = \frac{2 π}{T} = 20 r a d / s \\ x = 0.25 m \\ m g = - k x, k = 392.4 \\ 2 π \sqrt{\frac{m}{k}} = 0.1 π \end{array}$

Putting the value of k

m = 0.98 kg

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