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Q.

The scale of galvanometer of resistance 100Ω contains 25 divisions. It gives a deflection of one division on passing a current of 4×10-4 ampere. The resistance, in ohms, to be added to it, so that it may become a voltmeter of range 2.5 volt, is

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a

150

b

100

c

250

d

300

answer is B.

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Detailed Solution

∵V=2.5v, G=100Ω,ig=4×10−4×25AV=ig(G+R), 2.5=25×10−4(100+R)∴R=150Ω

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