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Q.

The schrodinger wave equation for hydrogen atom is 
Ψ(radial)=1164za03/2(σ1)σ28σ+12eσ/2
where a0 and z are the constant in which answer can be expressed and σ=2zra0 minimum and maximum position of radial nodes from nucleus are

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a

a02Z,3a0Z

b

a02Z,4a0Z

c

a02Z,a0Z

d

a0Z,3a0Z

answer is C.

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Detailed Solution

(c) Probability of finding e is zero implies that
ψ2=0 or ψ=0
(σ1)=0σ=1
or r1=a02z or σ28σ+12=0
and (σ6)(σ2)=0
σ=6,r=3a0z;σ=2,r=a0z;r2=3a0z

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