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Q.

The section of a window consists of a rectangle surmounted by an equilateral triangle. If the perimeters be given as 16m, find the dimensions of the window in order that the maximum amount of light may be admitted.


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a

2, 5

b

3, 3.5

c

3.75, 2.375

d

4, 2 

answer is C.

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Detailed Solution

Given,
Window’s perimeter=16 m
Suppose ABCD is a rectangle and CDE is an equilateral triangle.
Question ImageIn this figure,
AB=x BC=y
As, perimeter is 16 m. Thus,
3x+2y=16y=16-3x2       ….(1)
Area of total figure (A) is sum of the area of triangle and area of rectangle. Thus,
A=34x2+xy       since area of equilateral=34x2 area of reactangle =xy
Put value of y from equation 1,
A=34x2+16-3x2.....(2)
Differentiate it with respect to x,
dAdx=ddx34x2+16x-3x22
dAdx=34(2x)+16-16x2
dAdx=32(x)+8-3x......(2)
Now,
=32(x)+8-3x=0          (dAdx=0 for maxima or minima)
x3-32=8x6-32=8x6-3=16x=16(6-3)
Again, differentiate (2) with respect to x,
d2Adx2=32-3<0
Thus, area is maximum,
x=166-3
Put this value in equation 1,
y=16-3166-32
y=16-486-32y=16(6-3)-482(6-3)
y=96-163-482(6-3)
y=48-1632(6-3)
y=24-83(6-3)
Thus,
Breadth, x=16(6-3)3.75
Length, y=24-83(6-3)2.375
Hence, the correct option is (3).
 
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