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Q.

The segment of a ring, whose linear charge density is $8 C / cm$ , then the electric field at point ' O ' is $x \times 10^{13} V / m$ , then $x / 6$ is

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answer is 3.

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Detailed Solution

$\begin{array}{l} E = \frac{λ}{2 {πϵ}_{0} r} \sin \frac{θ}{2} = \frac{8}{2 {πϵ}_{0} 4 \times 10^{- 2} \times 10^{- 2}} \sin \frac{60}{2} \\ = \frac{16 \times 9 \times 10^{9}}{4 \times 10^{- 2} \times 10^{- 2}} (\frac{1}{2}) = 18 \times 10^{13} V / m \end{array}$

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