The self ionization constant for pure formic acid, $K = [{HCOOH}_{2}^{+}] [{HCOO}^{- 1}]$ has been estimated as 10-6 at room temperature. The density of formic acid is $1.15 g / {cm}^{3}$ . The percentage of formic acid molecules in pure formic acid that are converted to format ion :

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0.002%

0.004%

0.006%

0.008%

answer is B.

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Detailed Solution

$\begin{array}{l} 2 HCOOH ⇌ {HCOO}^{-} + {HCOOH}_{2}^{+}; \begin{array}{r} c \cdot α = 10^{- 3} \\ (given) \end{array} \\ C (1 - α) C α C α C = \frac{1000 \times 1.15}{46} \\ \Rightarrow % α = 0.004 \end{array}$

Thus, the formic acid molecules in pure formic acid that are 0.004%.

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