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The sequence given below represents flow of energy in a grassland ecosystem.
Grass $\to$ Grasshopper $\to$ Frog $\to$ Snake $\to$ Hawk
If GPP is 3000 K Cal and R is 20% at the producer level, estimate the secondary productivity of snake (as per 10 percent law).

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2.4 K Cal

3.0 K Cal

0.24 K Cal

0.30 K Cal

answer is A.

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Detailed Solution

GPP = 3000 K Cal

R = 20% of GPP = $3000 \times \frac{20}{100} = 600 K Cal$

NPP = GPP – R

NPP = 3000 – 600 = 2400 K Cal

As per 10 per cent law :

Grass (2400 K Cal) $\to$ Grasshopper (240 K Cal) $\to$ Frog (24 K Cal) $\to$ Snake (2.4 K Cal) $\to$ Hawk (0.24 K Cal)

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