Q.

The sequence given below represents flow of energy in a grassland ecosystem.      

Grass Grasshopper Frog Snake Hawk 

If GPP is 3000 K Cal and R is 20% at the producer level, estimate the secondary productivity of snake (as per 10 percent law).

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a

0.30 K Cal

b

3.0 K Cal

c

2.4 K Cal

d

0.24 K Cal

answer is A.

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Detailed Solution

GPP = 3000 K Cal

R = 20% of GPP = 3000×20100=600KCal

NPP = GPP – R

NPP = 3000 – 600 = 2400 K Cal

As per 10 per cent law :

Grass (2400 K Cal) Grasshopper (240 K Cal)Frog (24 K Cal)Snake (2.4 K Cal)Hawk (0.24 K Cal) 

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The sequence given below represents flow of energy in a grassland ecosystem.      Grass→ Grasshopper→ Frog→ Snake→ Hawk If GPP is 3000 K Cal and R is 20% at the producer level, estimate the secondary productivity of snake (as per 10 percent law).