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Q.

The set of all values of λ for which the equation cos22x2sin4x2cos2x=λ has a real solution x, is

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a

1,12

b

32,1

c

[2,1]

d

2,32

answer is B.

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Detailed Solution

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cos22x2sin4x2cos2x=λcos22x12(1cos2x)2(1+cos2x)=λ2cos22x1+cos22x2cos2x22cos2x=2λcos22x3=2λλ32,1

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