Q.

The set of homoegeneous equations: tx+(t+1)y+(t1)z=0;  (t+1)x+ty+(t+2)z=0;  (t1)x+(t+2)y+tz=0  has non-trivial solution for  

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a

One value of t

b

Three values of t

c

Two values of t

d

No value of t

answer is C.

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Detailed Solution

Determinant of coefficients =|tt+1t1t+1tt+2t1t+2t|=|t11t+111t131|  =|t112t+1002t140|=4(2t+1)  For non-trivial solution t=12.

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