The set of values of ‘x’ for which tan3x-tan2x1+tan3xtan2x=1 is

tan3x-tan2x1+tan3x tan2x=1 tan(3x-2x)=1 tan x=1 ⇒ x=π4 is not possible

The set of values of ‘x’ for which tan3x-tan2x1+tan3xtan2x=1 is

tan3x-tan2x1+tan3x tan2x=1 tan(3x-2x)=1 tan x=1 ⇒ x=π4 is not possible

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The set of values of ‘x’ for which $\frac{\tan 3 x - \tan 2 x}{1 + \tan 3 x \tan 2 x} = 1 i s$

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$θ$

$\{π / 4\}$

$\{n π + \frac{π}{4}; n \in z\}$

$\{2 n π + \frac{π}{4}; n \in z\}$

answer is A.

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$\frac{\tan 3 x - \tan 2 x}{1 + \tan 3 x \tan 2 x} = 1 \tan (3 x - 2 x) = 1 \tan x = 1 \Rightarrow x = \frac{π}{4} is not possible$

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The set of values of ‘x’ for which tan3x-tan2x1+tan3xtan2x=1 is

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The set of values of ‘x’ for which $\frac{\tan 3 x - \tan 2 x}{1 + \tan 3 x \tan 2 x} = 1 i s$