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Q.

The set of values of ‘x’ satisfying the equation $\sqrt{2 x - 5} < - 5$ i s

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a

$(0, \infty)$

b

$(- \infty, \frac{5}{2}]$

c

$ϕ$

d

$[\frac{5}{2}, \infty)$

answer is A.

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Detailed Solution

2x - 5 ≥ 0; but $\sqrt{}$ cannot be negative

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