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The shaft of a motor is making 1260 rpm. The torque supplied by the motor is 100Nm. The power of motor is

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13.2 kw

4.8 kw

100km

21kw

answer is C.

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Detailed Solution

$P = τ ω = 100 \times 2 \times \frac{22}{7} \times \frac{1260}{60} = 13.2 k w$

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