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Q.

The SHM of a particle is given by xt=5 cos2πt+π4 in MKS units. Calculate the displacement and the magnitude of acceleration of the particle at t=1.5s

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a

-3.54 m, 140 m/s2

b

-3.0m, 100 m/s2

c

+2.54m, 200 m/s2

d

+3.55m, 120 m/s2

answer is C.

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Detailed Solution

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Displacement xt=5 cos2π×32×π4=5 cos13π4=-3.54mVelocityv=dxdt=-10πsin2π+π4 

Acceleration, a=dvdt=-20π2cos2πt+π4

=-20π2cos2πt+π4=20π2cos13π4=140 m/s2

 

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