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Q.

The shortest distance between the lines x−a+dα−δ=y−aα=z−a−dα+δ,x−b+cβ−γ=y−bβ=z−b−cβ+γ is

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a

a+b+c+d

b

α+β+γ

c

aα+bβ+cγ

d

0

answer is D.

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Detailed Solution

=a−d−b−ca−ba+d−b−cα−δαα+δβ−γββ+γ

C1→C1−C2,C3→C3−C2

c−da−bd−c−δαδ−γβγ=0

(∵C1 and C3 are identical)

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