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The shortest wavelength of H atom in the Lyman series is λ1 .

 The longest wavelength in the Balmer series of He+ is :

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a
36λ15
b
27λ15
c
5λ19
d
9λ15

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detailed solution

Correct option is D

Shortest wavelength  → Max energy ( ∞ → 1 ) (Lyman series)

1λ1=RH×12112-0 RH=1λ1 For balmer series  1λ1=RH×22122-132 1λ1=5RH9 λ1==95RH= 9λ15 

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