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The side of a cube is measured by Vernier Calipers (10 divisions of the vernier scale coincide with 9 divisions of the main scale, where 1 division of main scale in 1 mm). The main scale reads 10mm and first division of Vernier scale coincides with the main scale. The mass of the cube is 2.736g. Find the density of the cube in appropriate significant figures.

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$2.6 {gcm}^{- 3}$

$2.565 {gcm}^{- 3}$

$2.76 g / {cm}^{- 3}$

$2.66 {gcm}^{- 3}$

answer is A.

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Detailed Solution

Least count of Vernier Calipers.

$LC = \frac{1 division of main scale}{Number of divisions in vernier scale} = \frac{1}{10} = 0.1 mm$

$Side of cube = 10 mm + 1 \times 0.1 mm = 10.1 mm = 1.01 cm$

$Now, density = \frac{Mass}{volume} = \frac{2.736 g}{{(1.01)}^{3} {cm}^{3}} = 2.66 {gcm}^{- 3}$

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