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Q.

The side of a square is increasing at the rate of 0.2cm/s. The rate of increase of perimeter w.r.t. time is

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a

0.6 cm/s

b

0.4 cm/s

c

0.2 cm/s

d

0.8 cm/s

answer is D.

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Detailed Solution

Perimeter = 4a, where a= side of square
Rate of increase of perimeter w.r.t. time = 4dadt = 4(0.2) =0 .8 cm/s

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