The sides of a triangle are in the ratio $1:\sqrt{3}:2$ then the angles of the triangle are in the ratio

Let  $a:b:c=1:\sqrt{3}:2\Rightarrow c^2=a^2+b^2$
$\therefore \Delta le$ is right angled at $C$

$\left(or\right)\overline{)C}=90° \& \frac{a}{b}=\frac{1}{\sqrt{3}}.$

$\tan A=\frac{a}{b}=\frac{1}{\sqrt{3}}$
$\Rightarrow \overline{)A}=30°\&\overline{)B}=60°$
$\therefore A:B:C=1:2:3$