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The silver halide which is the least soluble in ${NH}_{4} OH$ ;

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$AgF$

$AgI$

$AgBr$

$AgCl$

answer is A.

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Detailed Solution

Agl seems to be the least soluble mainly because it has the most covalent character, and the two atoms have the most similar atomic radii in context, thereby forming the strongest bond in the lattice structure.

Hence, the correct answer is option A) Agl.

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