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Q.

The sine function having period 3 is

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a

$\sin (\frac{2 π x}{3})$

b

$\tan π x$

c

$\sin π x$

d

$\tan 3 π x$

answer is D.

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Detailed Solution

The function having period 3 is

$= \sin (\frac{2 π x}{3}) [∵ Period = \frac{2 π}{\frac{2 π}{3}} = 3]$

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The sine function having period 3 is