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Q.

The skate board negotiating the circular surface of radius 4⋅5 m [shown in figure]. At θ =45o, its speed of

Question Image

centre of mass is 6 m/s. The combined mass of skate board and the person is 70 kg and his centre of mass is 0.75 m from the surface. The normal reaction between the surface and the skate board wheel is

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a

zero

b

500 N

c

2040 N 

d

1167 N

answer is C.

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Detailed Solution

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From figure, N−mgcos⁡θ=mv2/r

Here,     OC=4⋅5−0⋅75=3⋅75m,θ=45∘,m=70kg

V=6m/s  and  r=4⋅5m

∴ N=mv2r+mgcos⁡θ

Substituting the values, wo get N = 1167 N

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