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Q.

The slant height of a cone is fixed at 7cm. The rate of increase in the volume of the cone corresponding to the rate of increase of 0.3 cm/s in the height when h = 4cm is ______ cc/sec

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answer is 0.31.

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Detailed Solution

V=13πr2h=13πl2−h2h=13πl2h−h3

⇒dvdt=13πl2−3h2dhdt=13π49−3(4)20.3

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