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The slope m of a tangent through the point (7,1) to circle $x^{2} + y^{2} = 25$ satisfies the equation

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$12 m^{2} + 7 m - 12 = 0$

$12 m^{2} + 7 m + 9 = 0$

$12 m^{2} - 7 m - 12 = 0$

$12 m^{2} + 7 m + 12 = 0$

answer is C.

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Detailed Solution

$r = 5, y = m x \pm r \sqrt{1 + m^{2}}$ It is passing though (7,1)

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