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The slopes of the tangents at the points where the curve $y = x^{2} - 4 x$ intersects the x - axis is

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$\pm 4$

answer is D.

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Detailed Solution

Put y = 0 then x=0 or 4, $\frac{d y}{d x} = 2 x - 4 t h e n s l o p e o f \tan g e n t a t (0, 0) i s - 4, a t (4, 0) i s 4$

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