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The smallest division on main scale of a Vernier calipers is 1 mm and 10 Vernier divisions coincide with 9 main scale divisions. While measuring the length of a wire, the zero mark of the Vernier scale lies between 10.2 cm and 10.3 cm and third division of Vernier scale coincides with a main scale division. Find the length of the wire

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10.33 cm

10.2 cm

10.23 cm

10.03 cm

answer is D.

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Detailed Solution

$LC = \frac{1 MSD}{No . of VSD' s} = \frac{1}{10} mm = 0.01 cm Length = MSR + VC (LC) = 10.2 + 3 (0.01) = 10.23 cm$

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