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The smallest division on main scale of a vernier callipers is $1 mm$ and 10 vernier divisions coincide with 9 main scale divisions. While measuring the length of a line, the zero mark of the vernier scale lies between $10.2 cm$ and $10.3 cm$ and the third division of vernier scale coincides with a main scale division. Determine the least count of the callipers.

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An Intiative by Sri Chaitanya

0.01 cm

0.001 cm

0.1 cm

1 cm

answer is A.

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Detailed Solution

$Least Count (LC) = \frac{Smallest division on main scale}{Number of divisions on vernier scale}$

$= \frac{1}{10} mm = 0.1 mm = 0.01 cm$

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