The smallest division on the main scale of a Vernier calipers is 0.1cm. Ten divisions of the Vernier scale correspond to nine divisions of the main scale. The figure below on the left shows the reading of this calipers with no gap between its two jaws. The figure on the right shows the reading with a solid sphere held between the jaws. The correct diameter of the sphere is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

3.15 cm

4.07 cm

4.16 cm

4.11 cm

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given 10 VSD = 9 MSD
Least count = $\frac{1 M S D}{10} = 0.1 m m$
As '0' of V.S. lies before '0' of M.S.
Zero error = –[10 – 6] L.C.
= – 4 × 0.01 cm
= –0.04 cm
Reading = 4.1 cm + 2 × LC
= 4.1 cm + 2 × 0.01 cm
= 4.12 cm
True diameter = Reading – Zero error
= 4.12 – (–0.04) cm = 4.16 cm

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE