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Q.

The smallest positive value of ‘p’ for which the equation cos(Psinx)=sin(Pcosx) has solution is 0x2π is

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a

π22

b

π2

c

3π22

d

π2

answer is C.

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Detailed Solution

cos(Psinx)=sin(Pcosx)

cos(Psinx)=cos(π2Pcosx)

Psinx+Pcosx=2nπ+π2

PsinxPcosx=2nππ2

P(sinxcosx)=2nπ±π2

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