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Q.

The smallest value of $x^{2} - 3 x + 3$ in the interval $(- 3, 3 / 2)$ is

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a

$5$

b

$- 20$

c

$- 15$

d

$3 / 4$

answer is A.

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Detailed Solution

$x^{2} - 3 x + 3 = {(x - \frac{3}{2})}^{2} + \frac{3}{4}$

Therefore, smallest value is $\frac{3}{4}$ , which lie in $(- 3, \frac{3}{2})$

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